x^2+4x+7=(x+4)

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Solution for x^2+4x+7=(x+4) equation: 



x^2+4x+7=(x+4)

We move all terms to the left:

x^2+4x+7-((x+4))=0



We calculate terms in parentheses: -((x+4)), so:

(x+4)

We get rid of parentheses

x+4

Back to the equation:

-(x+4)



We get rid of parentheses

x^2+4x-x-4+7=0

We add all the numbers together, and all the variables

x^2+3x+3=0

a = 1; b = 3; c = +3;
Δ = b2-4ac
Δ = 32-4·1·3
Δ = -3
Delta is less than zero, so there is no solution for the equation

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